Problem
Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x.
You should preserve the original relative order of the nodes in each of the two partitions.
Example:
Input: head = 1->4->3->2->5->2, x = 3
Output: 1->2->2->4->3->5
class Solution { public ListNode partition(ListNode head, int x) { ListNode dummy1 = new ListNode(0); ListNode dummy2 = new ListNode(0); ListNode small = dummy1, large = dummy2; while (head != null) { if (head.val < x) { small.next = head; small = small.next; } else { large.next = head; large = large.next; } head = head.next; } small.next = dummy2.next; large.next = null; return dummy1.next; } }
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